(2p-2/p)/(10p-10/9p^2)

Solution for (2p-2/p)/(10p-10/9p^2) equation:

D( p )

p = 0

10*p-((10/9)*p^2) = 0

p = 0

p = 0

10*p-((10/9)*p^2) = 0

10*p-((10/9)*p^2) = 0

(-10/9)*p^2+10*p = 0

10*p-10/9*p^2 = 0

DELTA = 10^2-(-10/9*0*4)

DELTA = 100

DELTA > 0

p = (100^(1/2)-10)/(-10/9*2) or p = (-100^(1/2)-10)/(-10/9*2)

p = 0 or p = 9

p in (-oo:0) U (0:9) U (9:+oo)

(2*p-(2/p))/(10*p-((10/9)*p^2)) = 0

(2*p-2*p^-1)/((-10/9)*p^2+10*p) = 0

(2*p-2*p^-1)/(10*p-10/9*p^2) = 0

2*p-2*p^-1 = 0

2*p^-1*(p^2-1) = 0

1*p^2 = 1 // : 1

p^2 = 1

p^2 = 1 // ^ 1/2

abs(p) = 1

p = 1 or p = -1

2*p^-1*(p-1)*(p+1) = 0

10*p-10/9*p^2 = 0

10*p*(1-1/9*p) = 0

1-1/9*p = 0 // - 1

-1/9*p = -1 // : -1/9

p = -1/(-1/9)

p = 9

10*p*(p-9) = 0

(2*p^-1*(p-1)*(p+1))/(10*p*(p-9)) = 0

( 2*p^-1 )

2*p^-1 = 0 // : 2

p^-1 = 0

p naleu017Cy do O

( p+1 )

p+1 = 0 // - 1

p = -1

( p-1 )

p-1 = 0 // + 1

p = 1

p in { -1, 1 }